4.3 KiB
+++ title = "Analog to Digital Converters" author = ["Dehaeze Thomas"] keywords = ["electronics"] draft = false category = "equipment" +++
- Tags
- [Electronics]({{< relref "electronics.md" >}})
Types of Analog to Digital Converters
https://dewesoft.com/daq/types-of-adc-converters
- Delta Sigma (Baker 2011)
- Successive Approximation
Power Spectral Density of the Quantization Noise
This analysis is taken from here.
Let's note:
- \(q = \frac{\Delta V}{2^n}\) the quantization in [V], which is the corresponding value in [V] of the least significant bit
- \(\Delta V\) is the full range of the ADC in [V]
- \(n\) is the number of ADC's bits
- \(f_s\) is the sample frequency in [Hz]
Let's suppose that the ADC is ideal and the only noise comes from the quantization error. Interestingly, the noise amplitude is uniformly distributed.
The quantization noise can take a value between \(\pm q/2\), and the probability density function is constant in this range (i.e., it’s a uniform distribution). Since the integral of the probability density function is equal to one, its value will be \(1/q\) for \(-q/2 < e < q/2\) (Fig. 1).
{{< figure src="/ox-hugo/probability_density_function_adc.png" caption="<span class="figure-number">Figure 1: Probability density function \(p(e)\) of the ADC error \(e\)" >}}
Now, we can calculate the time average power of the quantization noise as
\begin{equation} P_q = \int_{-q/2}^{q/2} e^2 p(e) de = \frac{q^2}{12} \end{equation}
The other important parameter of a noise source is the power spectral density (PSD), which indicates how the noise power spreads in different frequency bands. To find the power spectral density, we need to calculate the Fourier transform of the autocorrelation function of the noise.
Assuming that the noise samples are not correlated with one another, we can approximate the autocorrelation function with a delta function in the time domain. Since the Fourier transform of a delta function is equal to one, the power spectral density will be frequency independent. Therefore, the quantization noise is white noise with total power equal to \(P_q = \frac{q^2}{12}\).
Thus, the two-sided PSD (from \(\frac{-f_s}{2}\) to \(\frac{f_s}{2}\)), we should divide the noise power \(P_q\) by \(f_s\):
\begin{equation} \int_{-f_s/2}^{f_s/2} \Gamma(f) d f = f_s \Gamma = \frac{q^2}{12} \end{equation}
Finally, the Power Spectral Density of the quantization noise of an ADC is equal to:
\begin{equation} \begin{aligned} \Gamma &= \frac{q^2}{12 f_s} \\ &= \frac{\left(\frac{\Delta V}{2^n}\right)^2}{12 f_s} \text{ in } \left[ \frac{V^2}{Hz} \right] \end{aligned} \end{equation}
Let's take a 18bits ADC with a range of +/-10V and a sample frequency of 10kHz.
The quantization is: \[ q = \frac{20}{2^{18}} = 0.000076 \ [V] = 76 \ [\mu V] \]
\[ \Gamma_Q = \frac{q^2}{12 f_N} = 4.85 \cdot 10^{-14} \quad [V^2/Hz] \]
{{< youtube b9lxtOJj3yU >}}
Also see (Kester 2005).
Link between required dynamic range and effective number of bits
{{< figure src="/ox-hugo/dynamic_range_enob.png" caption="<span class="figure-number">Figure 2: Relation between Dynamic range and required number of bits (effective)" >}}