Remove some parentheses
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@ -9193,8 +9193,8 @@ For these cases, the complementary filters analytical formula in Equation\nbsp{}
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\begin{subequations}\label{eq:detail_control_cf_2nd_order}
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\begin{subequations}\label{eq:detail_control_cf_2nd_order}
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\begin{align}
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\begin{align}
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H_L(s) &= \frac{(1+\alpha) (\frac{s}{\omega_0})+1}{\left((\frac{s}{\omega_0})+1\right) \left((\frac{s}{\omega_0})^2 + \alpha (\frac{s}{\omega_0}) + 1\right)}\\
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H_L(s) &= \frac{(1+\alpha) (\frac{s}{\omega_0})+1}{\left(\frac{s}{\omega_0}+1\right) \left((\frac{s}{\omega_0})^2 + \alpha \frac{s}{\omega_0} + 1\right)}\\
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H_H(s) &= \frac{(\frac{s}{\omega_0})^2 \left((\frac{s}{\omega_0})+1+\alpha\right)}{\left((\frac{s}{\omega_0})+1\right) \left((\frac{s}{\omega_0})^2 + \alpha (\frac{s}{\omega_0}) + 1\right)}
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H_H(s) &= \frac{(\frac{s}{\omega_0})^2 \left(\frac{s}{\omega_0}+1+\alpha\right)}{\left(\frac{s}{\omega_0}+1\right) \left((\frac{s}{\omega_0})^2 + \alpha \frac{s}{\omega_0} + 1\right)}
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\end{align}
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\end{align}
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\end{subequations}
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\end{subequations}
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