nass-simscape/org/motion_force_requirements.org
2020-03-23 10:05:32 +01:00

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#+TITLE: Motion and Force Requirements for the Nano-Hexapod
* Soft Hexapod
As the nano-hexapod is in series with the other stages, it must apply all the force required to move the sample.
If the nano-hexapod is soft (voice coil), its actuator must apply all the force such that the sample has the wanted motion.
In some sense, it does not use the fact that the other stage are participating to the displacement of the sample.
Let's take two examples:
- Sinus Ty translation at 1Hz with an amplitude of 5mm
- Long stroke hexapod has an offset of 10mm in X and the spindle is rotating
Thus the wanted motion is a circle with a radius of 10mm
If the sample if light (30Kg) => 60rpm
If the sample if heavy (100Kg) => 1rpm
From the motion, we compute the required acceleration by derive the displacement two times.
Then from the Newton's second law: $m \vec{a} = \sum \vec{F}$ we can compute the required force.
** Matlab Init :noexport:ignore:
#+begin_src matlab :tangle no :exports none :results silent :noweb yes :var current_dir=(file-name-directory buffer-file-name)
<<matlab-dir>>
#+end_src
#+begin_src matlab :exports none :results silent :noweb yes
<<matlab-init>>
#+end_src
** Example
The wanted motion is:
\begin{align*}
x &= d \cos(\omega t) \\
y &= d \sin(\omega t)
\end{align*}
The corresponding acceleration is thus:
\begin{align*}
\ddot{x} &= - d \omega^2 \cos(\omega t) \\
\ddot{y} &= - d \omega^2 \sin(\omega t)
\end{align*}
From the Newton's second law:
\begin{align*}
m \ddot{x} &= F_x \\
m \ddot{y} &= F_y
\end{align*}
Thus the applied forces should be:
\begin{align*}
F_x &= - m d \omega^2 \cos(\omega t) \\
F_y &= - m d \omega^2 \sin(\omega t)
\end{align*}
And the norm of the force is:
\[ |F| = \sqrt{F_x^2 + F_y^2} = m d \omega^2 \ [N] \]
For a Light sample:
#+begin_src matlab :results value replace
m = 30;
d = 10e-3;
w = 2*pi;
F = m*d*w^2;
ans = F
#+end_src
#+RESULTS:
: 11.844
For the Heavy sample:
#+begin_src matlab :results value replace
m = 80;
d = 10e-3;
w = 2*pi/60;
F = m*d*w^2
ans = F
#+end_src
#+RESULTS:
: 0.008773