Update Content - 2022-11-02

content/zettels/voice_coil_actuators.md

@@ -80,7 +80,7 @@ D\_f = \frac{F\_\max}{k}
 \end{equation}
 
 
-### Determine the required voice coil force {#determine-the-required-voice-coil-force}
+### Determine the required voice coil force as a function of the payload's resonance {#determine-the-required-voice-coil-force-as-a-function-of-the-payload-s-resonance}
 
 Let's fix `m` (payload mass) and `Df` (wanted motion induced by the voice coil).
 Then, let's vary `f0` and compute the corresponding `Dg`, `Fmax` and `k`.
@@ -104,7 +104,7 @@ Fmax = k * Df; % [N]
 {{< figure src="/ox-hugo/voice_coil_force_fct_f0.png" caption="<span class=\"figure-number\">Figure 1: </span>Required Voice Coil Force as a function of the paylaod resonance and corresponding deflection due to gravity (mass is 5kg, stroke is 5mm)" >}}
 
 
-### Determine the attainable stroke {#determine-the-attainable-stroke}
+### Determine the payload resonance as a function of the wanted stroke {#determine-the-payload-resonance-as-a-function-of-the-wanted-stroke}
 
 Let's fix `m` (payload mass) and `Fmax` (maximum force applied by the Voice coil).
 Then, let's vary `Df` and compute the corresponding `Dg`, `f0` and `k`.
@@ -127,6 +127,10 @@ Dg = m * g ./ k; % [m]
 
 {{< figure src="/ox-hugo/voice_coil_resonance_fct_stroke.png" caption="<span class=\"figure-number\">Figure 2: </span>Resonance frequency and deflection due to gravity as a function of the wanted stroke (Max voice coil force is 50N and payload mass is 5kg)" >}}
 
+<a id="figure--fig:voice-coil-stiffness-fct-stroke"></a>
+
+{{< figure src="/ox-hugo/voice_coil_stiffness_fct_stroke.png" caption="<span class=\"figure-number\">Figure 3: </span>Resonance frequency and deflection due to gravity as a function of the wanted stroke (Max voice coil force is 50N and payload mass is 5kg)" >}}
+
 
 ## Bibliography {#bibliography}