{{<figuresrc="/ox-hugo/morrison16_force_field_plates.svg"caption="Figure 2: The force field between two conducting plates with equal and opposite charges and spacing distance \\(h\\)">}}
{{<figuresrc="/ox-hugo/morrison16_electric_field_ground_plane.svg"caption="Figure 3: The electric field pattern of one circuit trace and two circuit traces over a ground plane">}}
The simplest path to use for this integration is the one of the concentric circles in Figure [6](#org198efb1), where \\(H\\) is constant and \\(r\\) is the distance from the conductor.
For an area of constant field intensity, the magnetic flux \\(\phi\\) is simply the product \\(BA\\) where \\(B\\) is in tesla, \\(A\\) is the area in square meters, and \\(\phi\\) is the flux in webers.
The voltage induced in a conducting coil is given by the **Faraday's law**:
\begin{equation} \label{eq:faraday\_law}
\boxed{V = n \frac{d\phi}{dt} = n A \frac{dB}{dt}}
\end{equation}
where \\(n\\) is the number of turns in the coil.
If the induction flux \\(B\\) increases linearly, a steady voltage \\(B\\) must exist at the coil ends.
V = n^2 A k \mu\_0 \frac{dI}{dt} = L \frac{dI}{dt}
\end{equation}
where \\(k\\) relates to the geometry of the coil.
Equation \eqref{eq:inductance_coil} states that if \\(V\\) is one volt, then for an inductance of one henry, the current will rise at the rate of one ampere per second.
One way to calculate the work stored in a magnetic field is to use Eq. \eqref{eq:inductance_coil}.
The voltage \\(V\\) applied to a coil results in a linearly increasing current.
At any time \\(t\\), the power \\(P\\) supplied is equal to \\(VI\\).
Power is the rate of change of energy or \\(P = d\bm{E}/dt\\) where \\(\bm{E}\\) is the stored energy in the inductance.
We then have the stored energy in an inductance:
\begin{equation} \label{eq:energy\_inductance}
\boxed{\bm{E} = L \int\_0^I I dI = \frac{1}{2} L I^2}
\end{equation}
<divclass="important">
<div></div>
An inductor stores field energy.
It does not dissipate energy.
</div>
The presence of a voltage \\(V\\) on the terminals of an inductor implies an electric field.
The movement of energy into the inductor thus requires both an electric and a magnetic field.
This is due to the Faraday's law that requires a voltage when changing magnetic flux couples to a coil.
<divclass="exampl">
<div></div>
Consider a 1mH inductor carrying a current of 0.1A.
The stored energy is \\(5 \times 10^{-4} J\\).
Assume the shunt capacitance equals 100pF.
When this energy is fully transferred to the capacitance, the voltage must be 3116 V.
This would probably destroy the component.
In order to absorb the stored magnetic field energy and avoid a high voltage, a reverse diode accross the coil can be used to provide a path for interrupted current flow.
This chapter is devoted to analog circuits that operate below 100kHz.
The techniques that are described can be applied to audio amplifiers, power supplies as well as instrumentation.
The availability of integrated circuits has simplified many aspects of analog circuit design.
Instrumentation must often handle long signal lines, reject ground potential differences, and maintain circuit stability.
The general problem of analog design is called signal conditioning, which includes gain, filtering, offsets, bridge balancing, common-mode rejection, transducer excitation and calibration.
Once a signal has sufficient resolution and the bandwidth has been controlled, the signal can be digitized and transmitted over a digital link to a computer.
This chapter treats the problems of conditioning signals before they are sampled and recorded.
Consider the simple amplifier circuit shown in Figure [9](#orgd60f7ec) with:
- \\(V\_1\\) the input lead
- \\(V\_2\\) the output lead
- \\(V\_3\\) the conducting enclosure which is floating and taken as the reference conductor
- \\(V\_4\\) a signal common or reference conductor
Every conductor pair has a mutual capacitance, which are shown in Figure [9](#orgd60f7ec) (b).
The equivalent circuit is shown in Figure [9](#orgd60f7ec) (c) and it is apparent that there is some feedback from the output to the input or the amplifier.
<aid="orgd60f7ec"></a>
{{<figuresrc="/ox-hugo/morrison16_parasitic_capacitance_amp.svg"caption="Figure 9: Parasitic capacitances in a simple circuit. (a) Field lines in a circuit. (b) Mutual capacitance diagram. (b) Circuit representation">}}
It is common practice in analog design to connect the enclosure to circuit common (Figure [10](#org412bfcb)).
When this connection is made, the feedback is removed and the enclosure no longer couples signals into the feedback structure.
The conductive enclosure is called a **shield**.
Connecting the signal common to the conductive enclosure is called "**grounding the shield**".
This "grounding" usually removed "hum" from the circuit.
<aid="org412bfcb"></a>
{{<figuresrc="/ox-hugo/morrison16_grounding_shield_amp.svg"caption="Figure 10: Grounding the shield to limit feedback">}}
Most practical circuits provide connections to external points.
To see the effect of making a _single_ external connection, open the conductive enclosure and connect the input circuit common to an external ground.
Figure [11](#org5d67d92) (a) shows this grounded connection surrounded by an extension of the enclosure called the _cable shield_.
A problem can be caused by an incorrect location of the connection between the cable shield and the enclosure.
In Figure [11](#org5d67d92) (a), the electromagnetic field in the area induces a voltage in the loop and a resulting current to flow in conductor (1)-(2).
This conductor being the common ground that might have a resistance \\(R\\) or \\(1\,\Omega\\), this current induced voltage that it added to the transmitted signal.
Our goal in this chapter is to find ways of keeping interference currents from flowing in any input signal conductor.
To remove this coupling, the shield connection to circuit common must be made at the point, where the circuit common connects to the external ground.
This connection is shown in Figure [11](#org5d67d92) (b).
This connection keeps the circulation of interference current on the outside of the shield.
There is only one point of zero signal potential external to the enclosure and that is where the signal common connects to an external hardware ground.
The input shield should not be connected to any other ground point.
The reason is simple.
If there is an external electromagnetic field, there will be current flow in the shield and a resulting voltage gradient.
A voltage gradient will couple interference capacitively to the signal conductors.
<divclass="important">
<div></div>
An input circuit shield should connect to the circuit common, where the signal common makes its connection to the source of signal.
Any other shield connection will introduce interference.
</div>
<divclass="important">
<div></div>
Shielding is not an issue of finding a "really good ground".
It is an issue of using the _right_ ground.
</div>
<aid="org5d67d92"></a>
{{<figuresrc="/ox-hugo/morrison16_enclosure_shield_1_2_leads.png"caption="Figure 11: (a) The problem of bringing one lead out of a shielded region. Unwanted current circulates in the signal lead 2. (b) The \\(E\\) field circulate current in the shield, not in the signal conductor.">}}
The basic analog problem is to condition a signal associated with one ground reference potential and transport this signal to a second ground reference potential without adding interference.
<aid="org75ed03f"></a>
{{<figuresrc="/ox-hugo/morrison16_two_ground_problem.svg"caption="Figure 13: The two-circuit enclosures used to transport signals between grounds">}}
Here are a few rule that will help in analog board layout:
1. Maintain a flow of signal and signal common from input to output.
The area between the signal path and the signal reference conductor should be kept small.
2. Components associated with the input should not be near output circuit components.
3. Power supply connections (DC voltages) should enter at the output and thread back toward the input.
This avoids common-impedance coupling (parasitic feedback).
4. The greatest attention should be paid to the input circuit geometry.
Lead length for components connecting to the input path should be kept short.
Another way of describing this requirements is to interconnect the components to minimize the amount of bare copper connected to the input signal path.
In vibration analysis, piezoelectric sensors are used which are electrically equivalent to a capacitor.
When a force is exerted to the piezoelectric material, charges or voltage are generated.
The relationship between charge and voltage is \\(V = Q/C\\) where \\(C\\) is the transducer capacitance.
The voltage on the transducer can be amplifier by a high-impedance amplifier.
The input cable capacitance attenuates the input signal and this makes calibration a function of cable length.
The preferred method of amplifying signals from piezoelectric transducers is to measure charge generation and not voltage generation.
The charge is first converted to a voltage and the voltage is then amplified.
This type of instrument is called a **charge amplifier**.
The basic feedback around an operational amplifier usually involves two resistors.
The voltage gain is simply the ratio of the two resistors.
If the resistors are replaced by capacitors, the gain is the ratio of reactances.
This feedback circuit is called a **charge converter**.
The charge on the input capacitor is transferred to the feedback capacitor.
If the feedback capacitor is smaller than the transducer capacitance by a factor of 100, then the voltage across the feedback capacitor will be 100 times greater than the open-circuit transducer voltage.
This feedback arrangement is shown in Figure [17](#org964dc8b).
The open-circuit input signal voltage is \\(Q/C\_T\\).
The output voltage is \\(Q/C\_{FB}\\).
The voltage gain is therefore \\(C\_T/C\_{FB}\\).
Note that there is essentially no voltage at the summing node \\(s\_p\\).
<divclass="important">
<div></div>
A charge converter does not amplifier charge.
It converts a charge signal to a voltage.
</div>
<aid="org964dc8b"></a>
{{<figuresrc="/ox-hugo/morrison16_charge_amplifier.svg"caption="Figure 17: A basic charge amplifier">}}
<aid="orgdd200ce"></a>
{{<figuresrc="/ox-hugo/morrison16_charge_amplifier_feedback_resistor.svg"caption="Figure 18: The resistor feedback arrangement to control the low-frequency response">}}