Re-export everything

content/book/morrison16_groun_shiel.md

@@ -125,7 +125,7 @@ And we see that \\(H\\) has units of amperes per meter.
 The magnetic field of a solenoid is shown in [Figure 7](#figure--fig:morrison16-solenoid).
 The field intensity inside the solenoid is nearly constant, while outside its intensity falls of rapidly.
 
-Using Ampere's law \ref{eq:ampere\_law:}
+Using Ampere's law \eqref{eq:ampere\_law:}
 
 \begin{equation}
 \oint H dl \approx n I l
@@ -187,12 +187,12 @@ V = n^2 A k \mu\_0 \frac{dI}{dt} = L \frac{dI}{dt}
 
 where \\(k\\) relates to the geometry of the coil.
 
-Equation \ref{eq:inductance\_coil} states that if \\(V\\) is one volt, then for an inductance of one henry, the current will rise at the rate of one ampere per second.
+Equation \eqref{eq:inductance\_coil} states that if \\(V\\) is one volt, then for an inductance of one henry, the current will rise at the rate of one ampere per second.
 
 
 ### The energy stored in an inductance {#the-energy-stored-in-an-inductance}
 
-One way to calculate the work stored in a magnetic field is to use Eq. \ref{eq:inductance\_coil}.
+One way to calculate the work stored in a magnetic field is to use Eq. \eqref{eq:inductance\_coil}.
 The voltage \\(V\\) applied to a coil results in a linearly increasing current.
 At any time \\(t\\), the power \\(P\\) supplied is equal to \\(VI\\).
 Power is the rate of change of energy or \\(P = d\bm{E}/dt\\) where \\(\bm{E}\\) is the stored energy in the inductance.